Answer:
f(x)=6 at x=6
Therefore, option 4 is correct.
Step-by-step explanation:
We have been given a function:
[tex]f(x)= [tex]f(x)=\begin{cases}3x^2+1 & \text{ if } -4<x<6 \\ 6 & \text{ if } 6\leq x<9 \end{cases}[/tex]
We have to find the value of f(x) where x =6
The function is 6 at x= 6 from the definition of the function. Because equal to sign is with 6
Therefore, option 4 is correct.
