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Which of the following is a solution of x^2 + 2x + 8?
4 + i times the square root of 7
āˆ’1 + i times the square root of 7
2 + i times the square root of 7
āˆ’4 + i times the square root of 7

Respuesta :

texaschic101
x^2 + 2x + 8 = 0
x^2 + 2x = -8
x^2 + 2x + 1 = -8 + 1
(x + 1)^2 = -7
x + 1 = (+-) sqrt -7
x = -1 (+-) sqrt -7

solution is : x = -1 + i * sqrt 7

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