when no base is stated, assume base 10
and [tex]log_a(b)=c[/tex] translates to [tex] a^c=b [/tex]
g(x)=1, hmm
1=1.1845-log x
times -1 both sides
-1=log x-1.1845
add 1.1845 to both sides
0.1845=log x
translate and assume base 10
[tex]10^{0.1845}=x[/tex]
that's the exact value of x such that g(x)=1
you can evaluate it yourself
