You are given the quantity 4 x plus 16 over 6 that is
[tex]\dfrac{4x+16}{6}.[/tex]
1. Note that numerator 4x+16 consists of two terms 4x and 16 that have common factor 4, then
[tex]4=4\cdot 1,\ 16=4\cdot 4[/tex]
and
[tex]4x+16=4(x+4).[/tex]
2. Since [tex]6=2\cdot 3,[/tex] then
[tex]\dfrac{4x+16}{6}=\dfrac{4(x+4)}{2\cdot 3}=\dfrac{2(x+4)}{3}.[/tex]
You get 2 open parentheses x plus 4 close parentheses over 3.
Answer: correct choice is 1
