the question is
What is the measure of the arc PO?
we know that
The measure of the external angle is the semidifference of the arcs that it covers.
so
m∠MNO=[tex] \frac{1}{2} *(arcPO-arcMO) [/tex]
[tex] 45=\frac{1}{2} *(arcPO-83)\\ 90+83=arcPO\\ arcPO=173\ degrees [/tex]
therefore
the answer is
the measure of the arc PO is equal to [tex] 173\ degrees [/tex]
