Respuesta :
2(3y − 1)(y − 3)
= 2(3y)(y) - 2(y) - 2(3y) (3) + 2(1)(3)
= 6y^2 -2y - 18y + 6
= 6y^2 - 20y + 6
answer
2(3y − 1)(y − 3) is the factored form of 6y^2 - 20y + 6
= 2(3y)(y) - 2(y) - 2(3y) (3) + 2(1)(3)
= 6y^2 -2y - 18y + 6
= 6y^2 - 20y + 6
answer
2(3y − 1)(y − 3) is the factored form of 6y^2 - 20y + 6
