aliciapadilla21 aliciapadilla21
  • 19-06-2017
  • Mathematics
contestada

What is the cube root of -1000p^12q^3

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cg582902 cg582902
  • 19-06-2017
The answer would be -10p64q^1 
since -10^3(p^4)^3 (q^1)^3 is -1000p^12q^3
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calculista
calculista calculista
  • 10-01-2019

Answer:

[tex](-10p^{4}q)[/tex]

Step-by-step explanation:

we have

[tex]\sqrt[3]{-1000p^{12}q^{3}}[/tex]

we know that

[tex]-1000p^{12}q^{3}=(-10)^{3} (p^{4})^{3}(q)^{3}=(-10p^{4}q)^{3}[/tex]

substitute in the expression

[tex]\sqrt[3]{-1000p^{12}q^{3}}=\sqrt[3]{(-10p^{4}q)^{3}}=(-10p^{4}q)[/tex]

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