Answer:
[tex](x-8)^{2}+(y-4)^{2}=16[/tex]
Step-by-step explanation:
we know that
The equation of a circle into center radius form is equal to
[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]
where
(h,k) is the radius of the circle
r is the radius of the circle
In this problem we have
[tex]r=4\ units[/tex]
[tex](h,k)=(8,4)[/tex]
substitute
[tex](x-8)^{2}+(y-4)^{2}=4^{2}[/tex]
[tex](x-8)^{2}+(y-4)^{2}=16[/tex]
