Respuesta :
Approximately 1.52g of H2 is required to complete this chemical reaction:
N2 + 3H2 = 2NH3
The masses: 28+6=34g
Hope could help :)
N2 + 3H2 = 2NH3
The masses: 28+6=34g
Hope could help :)
N₂ + 3H₂ = 2NH₃
m(N₂)=7.1 g
M(N₂)=28.0 g/mol
M(H₂)=2.0 g/mol
m(N₂)/M(N₂)=m(H₂)/3M(H₂)
m(H₂)=3M(H₂)m(N₂)/M(N₂)
m(H₂)=3*2.0*7.1/28.0=1.52 g
m(N₂)=7.1 g
M(N₂)=28.0 g/mol
M(H₂)=2.0 g/mol
m(N₂)/M(N₂)=m(H₂)/3M(H₂)
m(H₂)=3M(H₂)m(N₂)/M(N₂)
m(H₂)=3*2.0*7.1/28.0=1.52 g
