Answer:
[tex]f^{-1}(3)=7[/tex]
Step-by-step explanation:
Given : [tex]f(x)=\frac{2x-2}{4}[/tex]
To Find: [tex]f^{-1}(3)[/tex]
Solution:
[tex]y=\frac{2x-2}{4}[/tex]
Replace x with y and y with x
[tex]x=\frac{2y-2}{4}[/tex]
Now find the value of y
[tex]\frac{4x+2}{2}=y[/tex]
[tex]2x+1=y[/tex]
Thus [tex]f^{-1}(x)=2x+1[/tex]
Now, [tex]f^{-1}(3)=2(3)+1=6+1=7[/tex]
Hence [tex]f^{-1}(3)=7[/tex]
