Answer:
120
Step-by-step explanation:
Upon pondering the wording here, I am thinking this must be a permutation. The words "distinct digits" tell me, for some reason, that order matters. The formula for the permutations of this is
₆P₃ = [tex]\frac{6!}{(6-3)!}[/tex] which simplifies to
[tex]\frac{6!}{3!}=\frac{6*5*4*3!}{3!}=120[/tex]
