Since the x coefficients are + and - 12 T I would use elimination method to solve this system. -12x-5y = 40 12x -11y =88 Add the equations. -16y = 128 Divide both sides by-16 y = -8 Plug -8 back into either equation and solve for x. -12x -5(-8) = 40 -12x + 40 = 40 Subtract 40 from both sides. -12x = 0 Divide both sides by-12 x = 0 (0, -8)
