Answer: The factorized form is [tex](4x+3)(2x-1)=0[/tex]
Step-by-step explanation:
Since we have given that
[tex]8x^2+2x-3[/tex]
Since it is quadratic equation, so, it has two factors.
We need to factorise the above expression:
[tex]8x^2 + 2x - 3\\\\=8x^2+6x-4x-3\\\\=2x(4x+3)-1(4x+3)\\\\=(4x+3)(2x-1)[/tex]
Hence, the factorized form is [tex](4x+3)(2x-1)=0[/tex]
