Which function in vertex form is equivalent to f(x) = x^2 + 6x + 3?

f(x) = (x + 3)^2 + 3
f(x) = (x + 3)^2 − 6
f(x) = (x + 6)^2 + 3
f(x) = (x + 6)^2 − 6

Question

16-05-2017
Mathematics

contestada

Which function in vertex form is equivalent to f(x) = x^2 + 6x + 3?

f(x) = (x + 3)^2 + 3
f(x) = (x + 3)^2 − 6
f(x) = (x + 6)^2 + 3
f(x) = (x + 6)^2 − 6

Respuesta :

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WojtekR WojtekR · Answer 1 · 2017-05-16T06:15:37+02:00

WojtekR WojtekR

16-05-2017

[tex]f(x)=x^2+6x+3[/tex]

Complete the square:

[tex]x^2+6x+a^2\implies a=\dfrac{6x}{2x}=3\implies x^2+6x+3^3[/tex]

And we have:

[tex]f(x)=x^2+6x+3\\\\f(x)=x^2+6x+3^2-3^2+3\\\\f(x)=(x+3)^2-9+3\\\\\boxed{f(x)=(x+3)^2-6}[/tex]

Answer B.

Answer Link

Which function in vertex form is equivalent to f(x) = x^2 + 6x + 3? f(x) = (x + 3)^2 + 3 f(x) = (x + 3)^2 − 6 f(x) = (x + 6)^2 + 3 f(x) = (x + 6)^2 − 6

Respuesta :

Otras preguntas

Which function in vertex form is equivalent to f(x) = x^2 + 6x + 3?

f(x) = (x + 3)^2 + 3
f(x) = (x + 3)^2 − 6
f(x) = (x + 6)^2 + 3
f(x) = (x + 6)^2 − 6