randerson56
randerson56 randerson56
  • 17-04-2014
  • Mathematics
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how do u simplify 15x^4 y^2 over 40x^3 y^2 

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Аноним Аноним
  • 17-04-2014
[tex]\frac{15x^4y^2}{40x^3y^2}=\frac{3}{8}x^{4-3}y^{2-2}=\frac{3}{8}x^1y^0=\frac{3}{8}x[/tex]
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