-x^2+7x-3=0 multiply the expression by -1
x^2-7x+3=0 we will complete the square so subtract 3 from both sides
x^2-7x=-3 now halve the linear coefficient, -7/2, square it 49/4, and add that to both sides...
x^2-7x+49/4=49/4-3 now the left side is a perfect square...
(x-7/2)^2=(49-12)/3
(x-7/2)^2=37/3 take the square root of both sides...
x-7/2=±√(37/3) now add 7/2 to both sides...
x=7/2±√(37/3)
