so hmmm if we use the "intersecting chords theorem", the angle of 93°, is really 1/2 * (arcBC + arcAD)
thus [tex]\bf 93=\cfrac{1}{2}(\widehat{BC}+\widehat{AD})\implies 93=\cfrac{161+\widehat{AD}}{2}
\\\\\\
186=161+\widehat{AD}\implies 186-161=\widehat{AD}[/tex]
