➢225 mL of solution containing 0.486 mole of solute mol HCl. Use molarity as a conversion factor.Mol HCl = 2.5 L soln x 0.10 mol HCl by diluting 25.0 mL of 6.00 M HCl to a total volume of 50.0 Note: Vc and Vd do not have to be ➢The mass of MgCl2 in a 2.75 mole sample 3.447 g of CO2 and 1.647 g of H2O.
