Respuesta :

irspow
Three consecutive numbers are n, n+1, and n+2.  We are told that the sum of these is 99 so:

n+n+1+n+2=99

3n+3=99

3n=96

n=32

So the smallest number of the three is 32

check...

32+33+34=99

99=99
aefcajun95
x + x + 2 + x + 4 = 99
3x + 6 = 99
x + 2 = 33
x = 31

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