take the squar root of both sides and remember the positive and negative roots
remember [tex] \sqrt{ \frac{x}{y} } = \frac{ \sqrt{x} }{ \sqrt{y} } [/tex]
so
[tex]x^2= \frac{49 }{121 } [/tex]
square root both sides
[tex] x= \sqrt{ \frac{49}{121} } = \frac{ \sqrt{49} }{ \sqrt{121} }= +/-\frac{ 7 }{ 11 } [/tex]
x=-7/11 or 7/11
