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  • 19-03-2017
  • Chemistry
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In a 0.1000M solution of methanoic acid, [H+]=4.2 x 10^-3M. Calculate the Ka of this acid.

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Аноним Аноним
  • 31-03-2017
In order to determine the Ka of the compound, we can use the expression for the calculation of pH for weak acids which is expressed as:

pH = -0.5 log Ka
-log (H+) = -0.5 log Ka
-log (4.2x10^-3) = -0.5 log Ka
Ka = 1.764x10^-5

Hope this answers the question.
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