the product of two consecutive even integers is 728.What are the integers?

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18-03-2017
Advanced Placement (AP)

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the product of two consecutive even integers is 728.What are the integers?

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konrad509 konrad509 · Answer 1 · 2017-03-18T21:28:00+01:00

konrad509 konrad509

18-03-2017

[tex]2n\cdot(2n+2)=728\\ 4n^2+4n-728=0\\ n^2+n-182=0\\ n^2+14n-13n-182=0\\ n(n+14)-13(n+14)=0\\ (n-13)(n+14)=0\\ n=13 \vee n=-14\\\\ 2n=26 \vee 2n=-28\\ 2n+2=28 \vee 2n+2=-26[/tex]

26 nad -28 or -26 and 28

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