tatianathomas0929
tatianathomas0929 tatianathomas0929
  • 17-03-2017
  • Mathematics
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Question 17 please help

Question 17 please help class=

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ChandrikaP ChandrikaP
  • 17-03-2017
[tex] \sqrt{9x^2} / \sqrt{18y^2} [/tex]
after taking sqrt both side

3x/[tex] \sqrt{9*2y^2} [/tex]

3x/3y√2
x/√2y
multiply both denomenator and numerator by√2
√2x/2y

Answer is A

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