How much heat was absorbed or lost by the surroundings? use 4.184 j/goc for the specific heat of the solution. put your answer in units of kj and make sure the sign is correct?
to solve the amount heat that was added or lost in the surrounding, use the formula: q = m cp dt where q is the heat m is the mass of the substance cp is the specific heat of the subtance dt is the change in temperature ( t2 - t1 ) just substitute the given value
