Given the hypotenuse is 16[tex] \sqrt{3} [/tex] and this is a 30-60-90 triangle.
y is opposite the 30 do divide the hypotenuse by 2 = 8[tex] \sqrt{3} [/tex]
x is opposite the 60 so take the side opposite the 30 and multiply it by [tex] \sqrt{3} [/tex] to give 8 * 3 = 24
