Since we are given the amounts of the reactants available for reaction, we have to determine the limiting reactant. And use this amount to calculate for the theoretical yield.
55 g Na ( 1 mol / 22.99 g ) = 2.39 mol Na 67.2 f Cl2 ( 1 mol / 70.9 g ) = 0.95 mol Cl2
Therefore, the limiting reactant would be Cl2 since it is the one consumed completely.
0.95 Cl2 ( 1 mol NaCl / 1 mol Cl2) = 0.95 NaCl produced from the reaction
