Using the loop rule and deriving the differential equation for an LC circuit find the current (sign included) through the inductor at the instant t = 2.2 s if L = 3.7 H, C = 5.0 F. The initial charge at the capacitor is Qo = 3.2 C and the initial current through the inductor is lo = 0. = Number i Units

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16-12-2022
Physics

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Using the loop rule and deriving the differential equation for an LC circuit find the current (sign included) through the inductor at the instant t = 2.2 s if L = 3.7 H, C = 5.0 F. The initial charge at the capacitor is Qo = 3.2 C and the initial current through the inductor is lo = 0. = Number i Units

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kumargaurav1012000 kumargaurav1012000 · Answer 1 · 2022-12-20T11:52:28+01:00

Initial current via the inductor is lo = 0, and initial charge at the capacitor is Q-o = 3.2 C. The only two devices allowed by the loop rule.

Find the current (sign included) flowing through the inductor at the point t = 2.2 seconds using the loop rule and the differential equation derived for an LC circuit. Derive the differential equation for an LC circuit using the loop rule. To improve comprehension of complex concepts in electrical circuit analysis, such as inductance, capacitance, and reactance, By building up electric charges on two nearby surfaces, a capacitor is a device that stores electrical energy in an electric field. An RL circuit is one with resistance and self-inductance, and an RL circuit with a resistor.

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