Answer:
[tex]\textsf{C.} \quad d=\dfrac{2x+3}{p}-z[/tex]
Step-by-step explanation:
Given equation:
[tex]p(d+z)=2x+3[/tex]
Divide both sides by p:
[tex]\implies \dfrac{p(d+z)}{p}=\dfrac{2x+3}{p}[/tex]
[tex]\implies d+z=\dfrac{2x+3}{p}[/tex]
Subtract z from both sides:
[tex]\implies d+z-z=\dfrac{2x+3}{p}-z[/tex]
[tex]\implies d=\dfrac{2x+3}{p}-z[/tex]
