Answer: B(-2,-7)
Step-by-step explanation:
[tex]\displaystyle\\M(x_M,y_M)=(\frac{x_A+x_B}{2},\frac{y_A+y_B}{2}) \\\\x_A=2\ \ \ \ x_M=0\ \ \ \ y_A=-1\ \ \ \ y_M=-4\\\\x_M=\frac{x_A+x_B}{2} \\\\Multiply\ both\ parts\ of \ the \ equation\ by\ 2:\\2x_M=x_A+x_B\\\\\Rightarrow\ x_B=2x_M-x_A\\\Rightarrow \ x_B=2(0)-2\\\Rightarrow\ x_B=0-2\\\Rightarrow\ x_B=-2\\Similarly,\\y_B=2y_M-y_A\\y_B=2(-4)-(-1)1\\y_B=-8+1\\y_B=-7\\Thus,\\B(-2,-7)[/tex]
