Answer: Given -
- Initial velocity of the ball, u = 0 m/s
- final velocity of the ball, v = 12 m/s
- Time taken = 36 sec
To find -
- Acceleration of the ball.
Solution -
[tex]A=\frac{v-u}{t}\\A=\frac{12-0}{36} \\A=\frac{12}{36} \\A=0.33m/s^2[/tex]
Therefore, the acceleration of the ball is 0.33 m/s².
I hope this helps.
