= (-54)
Step-by-step explanation:
ATQ
4+2(x+6)^2
6(x^2+12x+216)=0 [ {a+b}^2 = a^2+2ab+b^2 ]
6x^2 +72x+216=0
Put the value of x=(-3)
So ,
6x^2 +72x+36=0
6(-3)^2+72(-3)+216=0
6×(-9)+72×(-3)+216=0
(-54)+(-216)+216=0
= -54
Hence, the solution is -54 at x=(-3).
Thank You
