Answer:
-14
Step-by-step explanation:
4(x-2)(x-3)+7(x-2)(x-5)+7(x-3)(x-5)
Let x =3
Find the value when x=3
4(x-2)(x-3)+7(x-2)(x-5)+7(x-3)(x-5)
Substitute x=3
4(3-2)(3-3)+7(3-2)(3-5)+7(3-3)(3-5)
Add and subtract inside the parentheses
4(1)(0)+7(1)(-2)+7(0)(-2)
Multiply
0 -14 +0
Add and Subtract
-14
