Answer: (2, -1)
Step-by-step explanation:
[tex]y=-3x^2 +12x-13\\\\y=-3(x^2 - 4x)-13\\\\y=-3\left(\left(x-2 \right)^{2}-4 \right)-13\\\\y=-3(x-2)^{2}+12-13\\\\y=-3(x-2)^2 - 1[/tex]
So, the vertex is (2, -1).
