Phillyg8542 Phillyg8542
  • 18-07-2022
  • Mathematics
contestada

A rectangle is 8 feet longer than it is wide. find the dimensions of the rectangle if its area is 345 sq-feet.

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tanvigupta426 tanvigupta426
  • 23-07-2022

The width of rectangle is 15 feet and the length of rectangle is 23 feet.

According to the statement

Width of rectangle = x

Length of rectangle = x+10

Area of rectangle = 345 sq-feet.

we know that the area of rectangle is

Area of rectangle = L*W

Substitute the values in it then

345 = (x) (x+8)

345= (x)^2 + 8x

(x)^2 + 8x - 345 = 0

By factorisation

(x-15) (x+23) = 0

So, width of rectangle is 15 feet and the length of rectangle is 23 feet.

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