Answer:
10000
Step-by-step explanation:
When computing a consecutive sum of integers with a difference of 1.
Use gauss's formula of (n/2)(first number + last number).
with n being the # of integers.
Since it is ascending and descending, it can be broken down into 2 sequences:
1 + 2 + 3 + ... + 99 and 1 + 2 + 3 + ... + 100.
Once each is calculated, add them up to find the value.
So:
1 + 2 + 3 + ... + 99 = (99/2)(100) = 4950.
1 + 2 + 3 + ... + 100 = (100/2)(101) = 5050.
4950 + 5050 = 10000
