The pOH of a solution with [OH] = 9.0 × 107 will be D (6.04).
A ph value is the measure of acidity and the basics of a substance or solution.
Given;
[OH] = 9.0 × 10^7
pOH = - log [OH⁻]
pOH = - log (9.0 x 10⁻⁷)
pOH = 6.0457
Hence, The pOH of a solution with [OH] = 9.0 × 107 will be D (6.04).
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