Answer:
= (25π - 24) cm²
Step-by-step explanation:
Area of the circle = πr²
= π(5)²
= 25π cm²
Area of ΔOAB = 2(Area of ΔOCB)
AB = 6 cm
OC = 5 - 1 = 4 cm
By applying Pythagoras theorem in ΔOCB,
OB² = OC² + BC²
5² = 4² + BC²
BC² = 25 - 16
BC = √9 = 3 cm
Area of ΔOCB = 1/2 (OC) (BC)
= 1/2 (4) (3)
= 6cm^2
Area of ΔAOB = 2(6) = 12 cm²
Area of ΔAOB = Area of ΔDOE = 12 cm²
Area of shaded region = 25π - (12 + 12)
= (25π - 24) cm²
