Answer:
[tex]f^{-1}(x) = \frac{x}{5}[/tex]
Step-by-step explanation:
[tex]f^{-1}\left( x\right) =y\Longleftrightarrow f\left( y\right) =x[/tex]
…………………………
f(y) = x
⇔ 5y = x
[tex]\Longleftrightarrow y =\frac{x}{5}[/tex]
[tex]\Longleftrightarrow f^{-1}(x) = \frac{x}{5}[/tex]
