Based on the above, if BE = EC and BC = 24 then the sum of the angle of DF = [12].
What is the Mid segments about?
Note that:
From the image attached,
DF ≅ BE
EF ≅ DB
So therefore, DF ≅ BE will be:
= [tex]\frac{1}{2} BC[/tex]
= [tex]\frac{1}{2} 24[/tex]
= 12
Thus, Based on the above, if BE = EC and BC = 24 then the sum of the angle of DF = [12].
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