Answer:
1
Step-by-step explanation:
let x be the number to be added to 5 and 3
expressing the ratios in fractional form
[tex]\frac{5+x}{3+x}[/tex] = [tex]\frac{3}{2}[/tex] ( cross- multiply )
3(3 + x) = 2(5 + x) ← distribute parenthesis on both sides
9 + 3x = 10 + 2x ( subtract 2x from both sides )
9 + x = 10 ( subtract 9 from both sides )
x = 1
then the number to be added to both is 1
