Respuesta :

ven22514

Answer:

f(x) = x² + 2x - 3

(x+3)(x-1)

Step-by-step explanation:

Zeroes are -3 and 1

Let α = -3 and β = 1

f(x) = x² - (α+β)x + (αβ)

= x² - (-3+1)x + (-3 × 1)

= x² - (-2)x + (-3)

= x² + 2x - 3

x²+2x-3

x² - x + 3x - 3

x(x-1) + 3(x-1)

(x+3)(x-1)

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