Answer:
[tex]\huge\boxed{\sf x =\{3,1\}}[/tex]
Step-by-step explanation:
Let the number be x
Given condition:
x² = 4x - 3
Subtract 4x to both sides and add 3 to both sides
x² - 4x + 3 = 0
Using mid-term break
x² - 3x - x + 3 = 0
Take common
x(x-3) - 1(x-3) = 0
Take (x-3) common
(x - 3)(x - 1) = 0
Using zero's method
Either,
x - 3 = 0 OR x - 1 = 0
x = 3 OR x = 1
[tex]\rule[225]{225}{2}[/tex]
