Answer:
[tex]x_1=-2,\: x_2=7[/tex]
Step-by-step explanation:
[tex]x(x-5)=14\\\\x^2-5x=14\\\\x^2-5x+(\frac{-5}{2})^2 =14+(\frac{-5}{2})^2\\\\x^2-5x+\frac{25}{4}=14+\frac{25}{4}\\\\x^2-5x+\frac{25}{4}=\frac{81}{4}\\ \\(x-\frac{5}{2})^2=\frac{81}{4}\\ \\x-\frac{5}{2}=\pm\frac{9}{2}\\ \\x=\frac{5}{2}\pm\frac{9}{2}\\ \\x_1=-2,\: x_2=7[/tex]
