The quotient of [tex](x^3 + 6x^2 + 11x + 6) \div (x^2 + 4x + 3)[/tex] is x + 2
How to determine the quotient?
The quotient expression is given as:
[tex](x^3 + 6x^2 + 11x + 6) \div (x^2 + 4x + 3)[/tex]
Expand both expressions
[tex](x + 3)(x + 2)(x +1) \div (x + 3)(x +1)[/tex]
Cancel out the common factors
x + 2
Hence, the quotient of [tex](x^3 + 6x^2 + 11x + 6) \div (x^2 + 4x + 3)[/tex] is x + 2
Read more about quotient expressions at:
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