Answer:
[tex]y = x^2 - 8x + 38[/tex]
Step-by-step explanation:
Hello!
The standard form of a quadratic is [tex]ax^2 + bx + c[/tex].
To convert the vertex form to standard form, we have to expand the parenthesis and add the constant.
Convert:
- [tex]y = (x - 4)^2 + 22[/tex]
- [tex]y =(x -4)(x-4) + 22[/tex]
- [tex]y = x^2 - 4x - 4x + 16 + 22[/tex]
- [tex]y = x^2 - 8x + 38[/tex]
The standard form is [tex]y = x^2 - 8x + 38[/tex]
