powhajswskoman powhajswskoman
  • 16-05-2022
  • Mathematics
contestada

please help!!!! the other boxes under 4 and 15/2 are 10 and 5

please help the other boxes under 4 and 152 are 10 and 5 class=

Respuesta :

jimrgrant1 jimrgrant1
  • 16-05-2022

Answer:

see explanation

Step-by-step explanation:

given that x and y are proportional relationships , then

y = kx ← k is the constant of proportionality

divide both sides by x

[tex]\frac{y}{x}[/tex] = k

using corresponding values of x and y from each table to find k

first table

k = [tex]\frac{10}{1}[/tex] = 10

second table

k = [tex]\frac{20}{4}[/tex] = 5

third table

k = [tex]\frac{15}{2}[/tex]

fourth table

k = [tex]\frac{4}{1}[/tex] = 4

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