Respuesta :

farahshehade

Answer:

this is not the full question

[tex]\\ \rm\Rrightarrow pH=-log[H^+][/tex]

[tex]\\ \rm\Rrightarrow pH=-log[2.5\times 10^{-6}][/tex]

[tex]\\ \rm\Rrightarrow pH=-log2.5-log10^{-6}[/tex]

[tex]\\ \rm\Rrightarrow pH=-0.398+6[/tex]

[tex]\\ \rm\Rrightarrow pH=5.602[/tex]

  • Acidic as pH<7

Otras preguntas