Considering the circuit described, it is found that the equivalent resistance is of 6.67 ohms.
It is given by the product divided by the sum of the resistances of the two resistors.
In this problem, the resistances are of 20-ohms and 10-ohms, hence:
EQr = (20 x 10)/(20 + 10) = 200/30 = 6.67 ohms.
The equivalent resistance is of 6.67 ohms.
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