★ 1st solve the given equation to find value of "s".
[tex]\sf{⇝4s+3=63} \\ \\ \sf{⇝arranging \: terms} \\ \\ \sf{⇝4s=63-3} \\ \\ \sf{⇝4s=60} \\ \\ \sf{⇝s=\cancel\frac{60}{4}} \\ \\ \sf{⇝s=15} \\ \\ [/tex]
★ substituting s= 15 to check whether the equation is true or not?
- 4(15)+3=63
- 60+3=63
- 63=63
- LHS=RHS
★ hence,the above equation is true !
[tex]\sf{\:мѕнαcкεя\: ♪...}[/tex]
