Step-by-step explanation:
given ponts,
(3,0)=(x1,y1)
(-6,-3)=(x2,y2)
we know,
Eqn of any line joining two points be,
(y-y1)={(y2-y1)/(x2-x1)}*(x-x1)
y-0={(-3-0)/(-6-3)}*(x-3)
y=(1/3)*(x-3)
y=(x-3)/3
3y=x-3
0=x-3y-3
x-3y-3=0
Therefore it is required eqn
